Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

4x+\left(x+6\right)\left(x-3\right)=x^{2}-8x+15
Variable x cannot be equal to any of the values -6,-4 since division by zero is not defined. Multiply both sides of the equation by \left(x+4\right)\left(x+6\right), the least common multiple of x^{2}+10x+24,x+4.
4x+x^{2}+3x-18=x^{2}-8x+15
Use the distributive property to multiply x+6 by x-3 and combine like terms.
7x+x^{2}-18=x^{2}-8x+15
Combine 4x and 3x to get 7x.
7x+x^{2}-18-x^{2}=-8x+15
Subtract x^{2} from both sides.
7x-18=-8x+15
Combine x^{2} and -x^{2} to get 0.
7x-18+8x=15
Add 8x to both sides.
15x-18=15
Combine 7x and 8x to get 15x.
15x=15+18
Add 18 to both sides.
15x=33
Add 15 and 18 to get 33.
x=\frac{33}{15}
Divide both sides by 15.
x=\frac{11}{5}
Reduce the fraction \frac{33}{15} to lowest terms by extracting and canceling out 3.