Solve 4.1-4/4.1^2-3*4.1-4

$$\frac{ 4.1-4 }{ { 4.1 }^{ 2 } -3 \cdot 4.1-4 }$$

Evaluate

$$\frac{10}{51}\approx 0.196078431$$

Solution Steps

Subtract 4 from 4.1 to get 0.1.

$$\frac{0.1}{4.1^{2}-3\times 4.1-4}$$

Calculate 4.1 to the power of 2 and get 16.81.

$$\frac{0.1}{16.81-3\times 4.1-4}$$

Multiply 3 and 4.1 to get 12.3.

$$\frac{0.1}{16.81-12.3-4}$$

Subtract 12.3 from 16.81 to get 4.51.

$$\frac{0.1}{4.51-4}$$

Subtract 4 from 4.51 to get 0.51.

$$\frac{0.1}{0.51}$$

Expand \frac{0.1}{0.51} by multiplying both numerator and the denominator by 100.

$$\frac{10}{51}$$

Factor

$$\frac{2 \cdot 5}{3 \cdot 17} = 0.19607843137254902$$