Solve 4-0/4-0=x--1/3--1

$$\frac{ 4-0 }{ 4-0 } = \frac{ x--1 }{ 3--1 }$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Cancel out 4 in both numerator and denominator.

$$1=\frac{x-\left(-1\right)}{3-\left(-1\right)}$$

The opposite of -1 is 1.

$$1=\frac{x+1}{3-\left(-1\right)}$$

The opposite of -1 is 1.

$$1=\frac{x+1}{3+1}$$

Add 3 and 1 to get 4.

$$1=\frac{x+1}{4}$$

Divide each term of x+1 by 4 to get \frac{1}{4}x+\frac{1}{4}.

$$1=\frac{1}{4}x+\frac{1}{4}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{4}x+\frac{1}{4}=1$$

Subtract \frac{1}{4} from both sides.

$$\frac{1}{4}x=1-\frac{1}{4}$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{1}{4}x=\frac{4}{4}-\frac{1}{4}$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{4}x=\frac{4-1}{4}$$

Subtract 1 from 4 to get 3.

$$\frac{1}{4}x=\frac{3}{4}$$

Multiply both sides by 4, the reciprocal of \frac{1}{4}.

$$x=\frac{3}{4}\times 4$$

Cancel out 4 and 4.

$$x=3$$