Solve 4(-5)(2)-(4^2)/4(-5)

$$\frac{ 4(-5)(2)-( { 4 }^{ 2 } ) }{ 4(-5) }$$

Evaluate

$$\frac{14}{5}=2.8$$

Solution Steps

Multiply 4 and -5 to get -20.

$$\frac{-20\times 2-4^{2}}{4\left(-5\right)}$$

Multiply -20 and 2 to get -40.

$$\frac{-40-4^{2}}{4\left(-5\right)}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{-40-16}{4\left(-5\right)}$$

Subtract 16 from -40 to get -56.

$$\frac{-56}{4\left(-5\right)}$$

Multiply 4 and -5 to get -20.

$$\frac{-56}{-20}$$

Reduce the fraction \frac{-56}{-20} to lowest terms by extracting and canceling out -4.

$$\frac{14}{5}$$

Factor

$$\frac{2 \cdot 7}{5} = 2\frac{4}{5} = 2.8$$