Solve 4*-4^2*4^circ/4^4

$$\frac{ 4 \times - { 4 }^{ 2 } \times 4 ^ { \circ } }{ { 4 }^{ 4 } }$$

Evaluate

$$-1$$

Solution Steps

Cancel out 4\times 4 in both numerator and denominator.

$$\frac{-4^{2}}{4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{-16}{4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{-16}{16}$$

Divide -16 by 16 to get -1.

$$-1$$

Factor

$$-1$$