Solve 4/7x-4=(x+4)*7/15

$$\frac{ 4 }{ 7 } x-4=(x+4) \times \frac{ 7 }{ 15 }$$

Solve for x

$$x=56$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+4 by \frac{7}{15}.

$$\frac{4}{7}x-4=x\times \frac{7}{15}+4\times \frac{7}{15}$$

Express 4\times \frac{7}{15} as a single fraction.

$$\frac{4}{7}x-4=x\times \frac{7}{15}+\frac{4\times 7}{15}$$

Multiply 4 and 7 to get 28.

$$\frac{4}{7}x-4=x\times \frac{7}{15}+\frac{28}{15}$$

Subtract x\times \frac{7}{15} from both sides.

$$\frac{4}{7}x-4-x\times \frac{7}{15}=\frac{28}{15}$$

Combine \frac{4}{7}x and -x\times \frac{7}{15} to get \frac{11}{105}x.

$$\frac{11}{105}x-4=\frac{28}{15}$$

Add 4 to both sides.

$$\frac{11}{105}x=\frac{28}{15}+4$$

Convert 4 to fraction \frac{60}{15}.

$$\frac{11}{105}x=\frac{28}{15}+\frac{60}{15}$$

Since \frac{28}{15} and \frac{60}{15} have the same denominator, add them by adding their numerators.

$$\frac{11}{105}x=\frac{28+60}{15}$$

Add 28 and 60 to get 88.

$$\frac{11}{105}x=\frac{88}{15}$$

Multiply both sides by \frac{105}{11}, the reciprocal of \frac{11}{105}.

$$x=\frac{88}{15}\times \frac{105}{11}$$

Multiply \frac{88}{15} times \frac{105}{11} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{88\times 105}{15\times 11}$$

Do the multiplications in the fraction \frac{88\times 105}{15\times 11}.

$$x=\frac{9240}{165}$$

Divide 9240 by 165 to get 56.

$$x=56$$