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\frac{4\left(\sqrt{13}+3\right)}{\left(\sqrt{13}-3\right)\left(\sqrt{13}+3\right)}
Rationalize the denominator of \frac{4}{\sqrt{13}-3} by multiplying numerator and denominator by \sqrt{13}+3.
\frac{4\left(\sqrt{13}+3\right)}{\left(\sqrt{13}\right)^{2}-3^{2}}
Consider \left(\sqrt{13}-3\right)\left(\sqrt{13}+3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{4\left(\sqrt{13}+3\right)}{13-9}
Square \sqrt{13}. Square 3.
\frac{4\left(\sqrt{13}+3\right)}{4}
Subtract 9 from 13 to get 4.
\sqrt{13}+3
Cancel out 4 and 4.