Solve 3y-2/3geq1/4

$$\frac{ 3y-2 }{ 3 } \geq \frac{ 1 }{ 4 }$$

Solve for y

$$y\geq \frac{11}{12}$$

Solution Steps

Multiply both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$3y-2\geq \frac{1}{4}\times 3$$

Multiply \frac{1}{4} and 3 to get \frac{3}{4}.

$$3y-2\geq \frac{3}{4}$$

Add 2 to both sides.

$$3y\geq \frac{3}{4}+2$$

Convert 2 to fraction \frac{8}{4}.

$$3y\geq \frac{3}{4}+\frac{8}{4}$$

Since \frac{3}{4} and \frac{8}{4} have the same denominator, add them by adding their numerators.

$$3y\geq \frac{3+8}{4}$$

Add 3 and 8 to get 11.

$$3y\geq \frac{11}{4}$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$y\geq \frac{\frac{11}{4}}{3}$$

Express \frac{\frac{11}{4}}{3} as a single fraction.

$$y\geq \frac{11}{4\times 3}$$

Multiply 4 and 3 to get 12.

$$y\geq \frac{11}{12}$$