Solve 3+2+1+3+1+2+2+3+3+1+3+3+3+3+2/15

$$\frac{ 3+2+1+3+1+2+2+3+3+1+3+3+3+3+2 }{ 15 }$$

Evaluate

$$\frac{7}{3}\approx 2.333333333$$

Solution Steps

Add 3 and 2 to get 5.

$$\frac{5+1+3+1+2+2+3+3+1+3+3+3+3+2}{15}$$

Add 5 and 1 to get 6.

$$\frac{6+3+1+2+2+3+3+1+3+3+3+3+2}{15}$$

Add 6 and 3 to get 9.

$$\frac{9+1+2+2+3+3+1+3+3+3+3+2}{15}$$

Add 9 and 1 to get 10.

$$\frac{10+2+2+3+3+1+3+3+3+3+2}{15}$$

Add 10 and 2 to get 12.

$$\frac{12+2+3+3+1+3+3+3+3+2}{15}$$

Add 12 and 2 to get 14.

$$\frac{14+3+3+1+3+3+3+3+2}{15}$$

Add 14 and 3 to get 17.

$$\frac{17+3+1+3+3+3+3+2}{15}$$

Add 17 and 3 to get 20.

$$\frac{20+1+3+3+3+3+2}{15}$$

Add 20 and 1 to get 21.

$$\frac{21+3+3+3+3+2}{15}$$

Add 21 and 3 to get 24.

$$\frac{24+3+3+3+2}{15}$$

Add 24 and 3 to get 27.

$$\frac{27+3+3+2}{15}$$

Add 27 and 3 to get 30.

$$\frac{30+3+2}{15}$$

Add 30 and 3 to get 33.

$$\frac{33+2}{15}$$

Add 33 and 2 to get 35.

$$\frac{35}{15}$$

Reduce the fraction \frac{35}{15} to lowest terms by extracting and canceling out 5.

$$\frac{7}{3}$$

Factor

$$\frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335$$