Factor
\frac{3\left(6y+1\right)\left(36y^{2}-6y+1\right)}{8}
Evaluate
81y^{3}+\frac{3}{8}
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\frac{3\left(1+216y^{3}\right)}{8}
Factor out \frac{3}{8}.
\left(6y+1\right)\left(36y^{2}-6y+1\right)
Consider 1+216y^{3}. Rewrite 1+216y^{3} as \left(6y\right)^{3}+1^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
\frac{3\left(6y+1\right)\left(36y^{2}-6y+1\right)}{8}
Rewrite the complete factored expression. Polynomial 36y^{2}-6y+1 is not factored since it does not have any rational roots.
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