Solve 3/4(2x+4)=x+19

$$\frac{ 3 }{ 4 } (2x+4)=x+19$$

Solve for x

$$x=32$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{3}{4} by 2x+4.

$$\frac{3}{4}\times 2x+\frac{3}{4}\times 4=x+19$$

Express \frac{3}{4}\times 2 as a single fraction.

$$\frac{3\times 2}{4}x+\frac{3}{4}\times 4=x+19$$

Multiply 3 and 2 to get 6.

$$\frac{6}{4}x+\frac{3}{4}\times 4=x+19$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}x+\frac{3}{4}\times 4=x+19$$

Cancel out 4 and 4.

$$\frac{3}{2}x+3=x+19$$

Subtract x from both sides.

$$\frac{3}{2}x+3-x=19$$

Combine \frac{3}{2}x and -x to get \frac{1}{2}x.

$$\frac{1}{2}x+3=19$$

Subtract 3 from both sides.

$$\frac{1}{2}x=19-3$$

Subtract 3 from 19 to get 16.

$$\frac{1}{2}x=16$$

Multiply both sides by 2, the reciprocal of \frac{1}{2}.

$$x=16\times 2$$

Multiply 16 and 2 to get 32.

$$x=32$$