Solve 2x+-3/4=-x-3-3/8

$$\frac{ 2x+-3 }{ 4 } = \frac{ -x-3-3 }{ 8 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8, the least common multiple of 4,8.

$$2\left(2x-3\right)=-x-3-3$$

Use the distributive property to multiply 2 by 2x-3.

$$4x-6=-x-3-3$$

Subtract 3 from -3 to get -6.

$$4x-6=-x-6$$

Add x to both sides.

$$4x-6+x=-6$$

Combine 4x and x to get 5x.

$$5x-6=-6$$

Add 6 to both sides.

$$5x=-6+6$$

Add -6 and 6 to get 0.

$$5x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 5 is not equal to 0, x must be equal to 0.

$$x=0$$