Solve 2x/x-23x/x-3

$$\frac{ 2x }{ x-2 } \frac{ 3x }{ x-3 }$$

Evaluate

$$\frac{6x^{2}}{\left(x-3\right)\left(x-2\right)}$$

Short Solution Steps

Multiply \frac{2x}{x-2} times \frac{3x}{x-3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2x\times 3x}{\left(x-2\right)\left(x-3\right)}$$

Multiply x and x to get x^{2}.

$$\frac{2x^{2}\times 3}{\left(x-2\right)\left(x-3\right)}$$

Multiply 2 and 3 to get 6.

$$\frac{6x^{2}}{\left(x-2\right)\left(x-3\right)}$$

Apply the distributive property by multiplying each term of x-2 by each term of x-3.

$$\frac{6x^{2}}{x^{2}-3x-2x+6}$$

Combine -3x and -2x to get -5x.

$$\frac{6x^{2}}{x^{2}-5x+6}$$

Factor

$$\frac{6x^{2}}{\left(x-3\right)\left(x-2\right)}$$