Solve 2a+48/2=left(6a+3right)div3

$$\frac{ 2a+48 }{ 2 } = \left( 6a+3 \right) \div 3$$

Solve for a

$$a=23$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 2,3.

$$3\left(2a+48\right)=2\left(6a+3\right)$$

Use the distributive property to multiply 3 by 2a+48.

$$6a+144=2\left(6a+3\right)$$

Use the distributive property to multiply 2 by 6a+3.

$$6a+144=12a+6$$

Subtract 12a from both sides.

$$6a+144-12a=6$$

Combine 6a and -12a to get -6a.

$$-6a+144=6$$

Subtract 144 from both sides.

$$-6a=6-144$$

Subtract 144 from 6 to get -138.

$$-6a=-138$$

Divide both sides by -6.

$$a=\frac{-138}{-6}$$

Divide -138 by -6 to get 23.

$$a=23$$