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\frac{2a\left(z+1\right)}{\left(z-1\right)\left(z+1\right)}-\frac{3a\left(z-1\right)}{\left(z-1\right)\left(z+1\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of z-1 and z+1 is \left(z-1\right)\left(z+1\right). Multiply \frac{2a}{z-1} times \frac{z+1}{z+1}. Multiply \frac{3a}{z+1} times \frac{z-1}{z-1}.
\frac{2a\left(z+1\right)-3a\left(z-1\right)}{\left(z-1\right)\left(z+1\right)}
Since \frac{2a\left(z+1\right)}{\left(z-1\right)\left(z+1\right)} and \frac{3a\left(z-1\right)}{\left(z-1\right)\left(z+1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{2az+2a-3az+3a}{\left(z-1\right)\left(z+1\right)}
Do the multiplications in 2a\left(z+1\right)-3a\left(z-1\right).
\frac{-az+5a}{\left(z-1\right)\left(z+1\right)}
Combine like terms in 2az+2a-3az+3a.
\frac{-az+5a}{z^{2}-1}
Expand \left(z-1\right)\left(z+1\right).