Solve 27/41*2/7+14/41*4/9

$$\frac{ 27 }{ 41 } \times \frac{ 2 }{ 7 } + \frac{ 14 }{ 41 } \times \frac{ 4 }{ 9 }$$

Evaluate

$$\frac{878}{2583}\approx 0.339914828$$

Solution Steps

Multiply \frac{27}{41} times \frac{2}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27\times 2}{41\times 7}+\frac{14}{41}\times \frac{4}{9}$$

Do the multiplications in the fraction \frac{27\times 2}{41\times 7}.

$$\frac{54}{287}+\frac{14}{41}\times \frac{4}{9}$$

Multiply \frac{14}{41} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{54}{287}+\frac{14\times 4}{41\times 9}$$

Do the multiplications in the fraction \frac{14\times 4}{41\times 9}.

$$\frac{54}{287}+\frac{56}{369}$$

Least common multiple of 287 and 369 is 2583. Convert \frac{54}{287} and \frac{56}{369} to fractions with denominator 2583.

$$\frac{486}{2583}+\frac{392}{2583}$$

Since \frac{486}{2583} and \frac{392}{2583} have the same denominator, add them by adding their numerators.

$$\frac{486+392}{2583}$$

Add 486 and 392 to get 878.

$$\frac{878}{2583}$$

Factor

$$\frac{2 \cdot 439}{3 ^ {2} \cdot 7 \cdot 41} = 0.33991482771970577$$