Solve 25/100div25/100-5/10*left(1-5/10+frac{1}{3}right)

$$\frac{ 25 }{ 100 } \div \frac { 25 } { 100 } - \frac{ 5 }{ 10 } \times \left( 1- \frac{ 5 }{ 10 } + \frac{ 1 }{ 3 } \right)$$

Evaluate

$$\frac{7}{12}\approx 0.583333333$$

Solution Steps

Divide \frac{25}{100} by \frac{25}{100} to get 1.

$$1-\frac{5}{10}\left(1-\frac{5}{10}+\frac{1}{3}\right)$$

Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$1-\frac{1}{2}\left(1-\frac{5}{10}+\frac{1}{3}\right)$$

Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$1-\frac{1}{2}\left(1-\frac{1}{2}+\frac{1}{3}\right)$$

Convert 1 to fraction \frac{2}{2}.

$$1-\frac{1}{2}\left(\frac{2}{2}-\frac{1}{2}+\frac{1}{3}\right)$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$1-\frac{1}{2}\left(\frac{2-1}{2}+\frac{1}{3}\right)$$

Subtract 1 from 2 to get 1.

$$1-\frac{1}{2}\left(\frac{1}{2}+\frac{1}{3}\right)$$

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{1}{3} to fractions with denominator 6.

$$1-\frac{1}{2}\left(\frac{3}{6}+\frac{2}{6}\right)$$

Since \frac{3}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.

$$1-\frac{1}{2}\times \frac{3+2}{6}$$

Add 3 and 2 to get 5.

$$1-\frac{1}{2}\times \frac{5}{6}$$

Multiply \frac{1}{2} times \frac{5}{6} by multiplying numerator times numerator and denominator times denominator.

$$1-\frac{1\times 5}{2\times 6}$$

Do the multiplications in the fraction \frac{1\times 5}{2\times 6}.

$$1-\frac{5}{12}$$

Convert 1 to fraction \frac{12}{12}.

$$\frac{12}{12}-\frac{5}{12}$$

Since \frac{12}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-5}{12}$$

Subtract 5 from 12 to get 7.

$$\frac{7}{12}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$$