Solve 24/100=18/100+(x-1)*0.6/100

$$\frac{ 24 }{ 100 } = \frac{ 18 }{ 100 } +(x-1) \times \frac{ 0.6 }{ 100 }$$

Solve for x

$$x=11$$

Steps for Solving Linear Equation

Reduce the fraction \frac{24}{100} to lowest terms by extracting and canceling out 4.

$$\frac{6}{25}=\frac{18}{100}+\left(x-1\right)\times \frac{0.6}{100}$$

Reduce the fraction \frac{18}{100} to lowest terms by extracting and canceling out 2.

$$\frac{6}{25}=\frac{9}{50}+\left(x-1\right)\times \frac{0.6}{100}$$

Expand \frac{0.6}{100} by multiplying both numerator and the denominator by 10.

$$\frac{6}{25}=\frac{9}{50}+\left(x-1\right)\times \frac{6}{1000}$$

Reduce the fraction \frac{6}{1000} to lowest terms by extracting and canceling out 2.

$$\frac{6}{25}=\frac{9}{50}+\left(x-1\right)\times \frac{3}{500}$$

Use the distributive property to multiply x-1 by \frac{3}{500}.

$$\frac{6}{25}=\frac{9}{50}+x\times \frac{3}{500}-\frac{3}{500}$$

Least common multiple of 50 and 500 is 500. Convert \frac{9}{50} and \frac{3}{500} to fractions with denominator 500.

$$\frac{6}{25}=\frac{90}{500}+x\times \frac{3}{500}-\frac{3}{500}$$

Since \frac{90}{500} and \frac{3}{500} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6}{25}=\frac{90-3}{500}+x\times \frac{3}{500}$$

Subtract 3 from 90 to get 87.

$$\frac{6}{25}=\frac{87}{500}+x\times \frac{3}{500}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{87}{500}+x\times \frac{3}{500}=\frac{6}{25}$$

Subtract \frac{87}{500} from both sides.

$$x\times \frac{3}{500}=\frac{6}{25}-\frac{87}{500}$$

Least common multiple of 25 and 500 is 500. Convert \frac{6}{25} and \frac{87}{500} to fractions with denominator 500.

$$x\times \frac{3}{500}=\frac{120}{500}-\frac{87}{500}$$

Since \frac{120}{500} and \frac{87}{500} have the same denominator, subtract them by subtracting their numerators.

$$x\times \frac{3}{500}=\frac{120-87}{500}$$

Subtract 87 from 120 to get 33.

$$x\times \frac{3}{500}=\frac{33}{500}$$

Multiply both sides by \frac{500}{3}, the reciprocal of \frac{3}{500}.

$$x=\frac{33}{500}\times \frac{500}{3}$$

Multiply \frac{33}{500} times \frac{500}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{33\times 500}{500\times 3}$$

Cancel out 500 in both numerator and denominator.

$$x=\frac{33}{3}$$

Divide 33 by 3 to get 11.

$$x=11$$