Solve 2-left(3-7right)5-5/3left|3-4right|+1

$$\frac{ 2- \left( 3-7 \right) 5-5 }{ 3 \left| 3-4 \right| +1 }$$

Evaluate

$$\frac{17}{4}=4.25$$

Solution Steps

Subtract 7 from 3 to get -4.

$$\frac{2-\left(-4\times 5\right)-5}{3|3-4|+1}$$

Multiply -4 and 5 to get -20.

$$\frac{2-\left(-20\right)-5}{3|3-4|+1}$$

The opposite of -20 is 20.

$$\frac{2+20-5}{3|3-4|+1}$$

Add 2 and 20 to get 22.

$$\frac{22-5}{3|3-4|+1}$$

Subtract 5 from 22 to get 17.

$$\frac{17}{3|3-4|+1}$$

Subtract 4 from 3 to get -1.

$$\frac{17}{3|-1|+1}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -1 is 1.

$$\frac{17}{3\times 1+1}$$

Multiply 3 and 1 to get 3.

$$\frac{17}{3+1}$$

Add 3 and 1 to get 4.

$$\frac{17}{4}$$

Factor

$$\frac{17}{2 ^ {2}} = 4\frac{1}{4} = 4.25$$