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\frac{1}{3}-\frac{2}{3}x=\frac{2}{5}
Swap sides so that all variable terms are on the left hand side.
-\frac{2}{3}x=\frac{2}{5}-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
-\frac{2}{3}x=\frac{6}{15}-\frac{5}{15}
Least common multiple of 5 and 3 is 15. Convert \frac{2}{5} and \frac{1}{3} to fractions with denominator 15.
-\frac{2}{3}x=\frac{6-5}{15}
Since \frac{6}{15} and \frac{5}{15} have the same denominator, subtract them by subtracting their numerators.
-\frac{2}{3}x=\frac{1}{15}
Subtract 5 from 6 to get 1.
x=\frac{1}{15}\left(-\frac{3}{2}\right)
Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.
x=\frac{1\left(-3\right)}{15\times 2}
Multiply \frac{1}{15} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-3}{30}
Do the multiplications in the fraction \frac{1\left(-3\right)}{15\times 2}.
x=-\frac{1}{10}
Reduce the fraction \frac{-3}{30} to lowest terms by extracting and canceling out 3.