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\frac{2}{3}x+2=\frac{34}{6}
Divide 8 by 4 to get 2.
\frac{2}{3}x+2=\frac{17}{3}
Reduce the fraction \frac{34}{6} to lowest terms by extracting and canceling out 2.
\frac{2}{3}x=\frac{17}{3}-2
Subtract 2 from both sides.
\frac{2}{3}x=\frac{17}{3}-\frac{6}{3}
Convert 2 to fraction \frac{6}{3}.
\frac{2}{3}x=\frac{17-6}{3}
Since \frac{17}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{3}x=\frac{11}{3}
Subtract 6 from 17 to get 11.
x=\frac{11}{3}\times \frac{3}{2}
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.
x=\frac{11\times 3}{3\times 2}
Multiply \frac{11}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{11}{2}
Cancel out 3 in both numerator and denominator.