Solve 2/2-3(1-2/4)=2/8-2

$$\frac{ 2 }{ 2 } -3(1- \frac{ 2 }{ 4 } )= \frac{ 2 }{ 8 } -2$$

Verify

Solution Steps

Divide 2 by 2 to get 1.

$$1-3\left(1-\frac{2}{4}\right)=\frac{2}{8}-2$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$1-3\left(1-\frac{1}{2}\right)=\frac{2}{8}-2$$

Convert 1 to fraction \frac{2}{2}.

$$1-3\left(\frac{2}{2}-\frac{1}{2}\right)=\frac{2}{8}-2$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$1-3\times \frac{2-1}{2}=\frac{2}{8}-2$$

Subtract 1 from 2 to get 1.

$$1-3\times \frac{1}{2}=\frac{2}{8}-2$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$1-\frac{3}{2}=\frac{2}{8}-2$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}-\frac{3}{2}=\frac{2}{8}-2$$

Since \frac{2}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-3}{2}=\frac{2}{8}-2$$

Subtract 3 from 2 to get -1.

$$-\frac{1}{2}=\frac{2}{8}-2$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{2}=\frac{1}{4}-2$$

Convert 2 to fraction \frac{8}{4}.

$$-\frac{1}{2}=\frac{1}{4}-\frac{8}{4}$$

Since \frac{1}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{2}=\frac{1-8}{4}$$

Subtract 8 from 1 to get -7.

$$-\frac{1}{2}=-\frac{7}{4}$$

Least common multiple of 2 and 4 is 4. Convert -\frac{1}{2} and -\frac{7}{4} to fractions with denominator 4.

$$-\frac{2}{4}=-\frac{7}{4}$$

Compare -\frac{2}{4} and -\frac{7}{4}.

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