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\frac{4\left(4x^{2}-9\right)}{9}
Factor out \frac{4}{9}.
\left(2x-3\right)\left(2x+3\right)
Consider 4x^{2}-9. Rewrite 4x^{2}-9 as \left(2x\right)^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{4\left(2x-3\right)\left(2x+3\right)}{9}
Rewrite the complete factored expression.