Solve 14a^4b^-3/-8a^8b^-5

$$\frac{ 14 { a }^{ 4 } { b }^{ -3 } }{ -8 { a }^{ 8 } { b }^{ -5 } }$$

Evaluate

$$-\frac{7b^{2}}{4a^{4}}$$

Solution Steps

Cancel out 2a^{4} in both numerator and denominator.

$$\frac{7b^{-3}}{-4b^{-5}a^{4}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{7b^{2}}{-4a^{4}}$$

Differentiate w.r.t. b

$$-\frac{7b}{2a^{4}}$$