Solve 11/15y+9/10=8/15

$$\frac{ 11 }{ 15 } y+ \frac{ 9 }{ 10 } = \frac{ 8 }{ 15 }$$

Solve for y

$$y=-\frac{1}{2}=-0.5$$

Steps for Solving Linear Equation

Subtract \frac{9}{10} from both sides.

$$\frac{11}{15}y=\frac{8}{15}-\frac{9}{10}$$

Least common multiple of 15 and 10 is 30. Convert \frac{8}{15} and \frac{9}{10} to fractions with denominator 30.

$$\frac{11}{15}y=\frac{16}{30}-\frac{27}{30}$$

Since \frac{16}{30} and \frac{27}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11}{15}y=\frac{16-27}{30}$$

Subtract 27 from 16 to get -11.

$$\frac{11}{15}y=-\frac{11}{30}$$

Multiply both sides by \frac{15}{11}, the reciprocal of \frac{11}{15}.

$$y=-\frac{11}{30}\times \frac{15}{11}$$

Multiply -\frac{11}{30} times \frac{15}{11} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{-11\times 15}{30\times 11}$$

Do the multiplications in the fraction \frac{-11\times 15}{30\times 11}.

$$y=\frac{-165}{330}$$

Reduce the fraction \frac{-165}{330} to lowest terms by extracting and canceling out 165.

$$y=-\frac{1}{2}$$