Solve 1-sin(30)/1+sin(30)=

$$\frac{ 1- \sin ( 30 ) }{ 1+ \sin ( 30 ) } =$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Get the value of \sin(30) from trigonometric values table.

$$\frac{1-\frac{1}{2}}{1+\sin(30)}$$

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\frac{\frac{1}{2}}{1+\sin(30)}$$

Get the value of \sin(30) from trigonometric values table.

$$\frac{\frac{1}{2}}{1+\frac{1}{2}}$$

Add 1 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{\frac{1}{2}}{\frac{3}{2}}$$

Divide \frac{1}{2} by \frac{3}{2} by multiplying \frac{1}{2} by the reciprocal of \frac{3}{2}.

$$\frac{1}{2}\times \frac{2}{3}$$

Multiply \frac{1}{2} and \frac{2}{3} to get \frac{1}{3}.

$$\frac{1}{3}$$