Solve 1-left|.5right|/1+left|.5right|

$$\frac{ 1- \left| .5 \right| }{ 1+ \left| .5 \right| }$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 0.5 is 0.5.

$$\frac{1-0.5}{1+|0.5|}$$

Subtract 0.5 from 1 to get 0.5.

$$\frac{0.5}{1+|0.5|}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 0.5 is 0.5.

$$\frac{0.5}{1+0.5}$$

Add 1 and 0.5 to get 1.5.

$$\frac{0.5}{1.5}$$

Expand \frac{0.5}{1.5} by multiplying both numerator and the denominator by 10.

$$\frac{5}{15}$$

Reduce the fraction \frac{5}{15} to lowest terms by extracting and canceling out 5.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$