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\frac{\frac{2}{2}-\frac{1}{2}}{\frac{3}{4}}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Convert 1 to fraction \frac{2}{2}.
\frac{\frac{2-1}{2}}{\frac{3}{4}}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{1}{2}}{\frac{3}{4}}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Subtract 1 from 2 to get 1.
\frac{1}{2}\times \frac{4}{3}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Divide \frac{1}{2} by \frac{3}{4} by multiplying \frac{1}{2} by the reciprocal of \frac{3}{4}.
\frac{1\times 4}{2\times 3}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Multiply \frac{1}{2} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.
\frac{4}{6}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Do the multiplications in the fraction \frac{1\times 4}{2\times 3}.
\frac{2}{3}+\frac{\frac{3}{2}-1}{2-\frac{1}{4}}
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.
\frac{2}{3}+\frac{\frac{3}{2}-\frac{2}{2}}{2-\frac{1}{4}}
Convert 1 to fraction \frac{2}{2}.
\frac{2}{3}+\frac{\frac{3-2}{2}}{2-\frac{1}{4}}
Since \frac{3}{2} and \frac{2}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{3}+\frac{\frac{1}{2}}{2-\frac{1}{4}}
Subtract 2 from 3 to get 1.
\frac{2}{3}+\frac{\frac{1}{2}}{\frac{8}{4}-\frac{1}{4}}
Convert 2 to fraction \frac{8}{4}.
\frac{2}{3}+\frac{\frac{1}{2}}{\frac{8-1}{4}}
Since \frac{8}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{3}+\frac{\frac{1}{2}}{\frac{7}{4}}
Subtract 1 from 8 to get 7.
\frac{2}{3}+\frac{1}{2}\times \frac{4}{7}
Divide \frac{1}{2} by \frac{7}{4} by multiplying \frac{1}{2} by the reciprocal of \frac{7}{4}.
\frac{2}{3}+\frac{1\times 4}{2\times 7}
Multiply \frac{1}{2} times \frac{4}{7} by multiplying numerator times numerator and denominator times denominator.
\frac{2}{3}+\frac{4}{14}
Do the multiplications in the fraction \frac{1\times 4}{2\times 7}.
\frac{2}{3}+\frac{2}{7}
Reduce the fraction \frac{4}{14} to lowest terms by extracting and canceling out 2.
\frac{14}{21}+\frac{6}{21}
Least common multiple of 3 and 7 is 21. Convert \frac{2}{3} and \frac{2}{7} to fractions with denominator 21.
\frac{14+6}{21}
Since \frac{14}{21} and \frac{6}{21} have the same denominator, add them by adding their numerators.
\frac{20}{21}
Add 14 and 6 to get 20.