Solve 1+2z/4xz-3+y/2xy

$$\frac{ 1+2z }{ 4xz } - \frac{ 3+y }{ 2xy }$$

Evaluate

$$\frac{y-6z}{4xyz}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4xz and 2xy is 4xyz. Multiply \frac{1+2z}{4xz} times \frac{y}{y}. Multiply \frac{3+y}{2xy} times \frac{2z}{2z}.

$$\frac{\left(1+2z\right)y}{4xyz}-\frac{\left(3+y\right)\times 2z}{4xyz}$$

Since \frac{\left(1+2z\right)y}{4xyz} and \frac{\left(3+y\right)\times 2z}{4xyz} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(1+2z\right)y-\left(3+y\right)\times 2z}{4xyz}$$

Do the multiplications in \left(1+2z\right)y-\left(3+y\right)\times 2z.

$$\frac{y+2zy-6z-2yz}{4xyz}$$

Combine like terms in y+2zy-6z-2yz.

$$\frac{y-6z}{4xyz}$$

Expand

$$\frac{y-6z}{4xyz}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4xz and 2xy is 4xyz. Multiply \frac{1+2z}{4xz} times \frac{y}{y}. Multiply \frac{3+y}{2xy} times \frac{2z}{2z}.

$$\frac{\left(1+2z\right)y}{4xyz}-\frac{\left(3+y\right)\times 2z}{4xyz}$$

Since \frac{\left(1+2z\right)y}{4xyz} and \frac{\left(3+y\right)\times 2z}{4xyz} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(1+2z\right)y-\left(3+y\right)\times 2z}{4xyz}$$

Do the multiplications in \left(1+2z\right)y-\left(3+y\right)\times 2z.

$$\frac{y+2zy-6z-2yz}{4xyz}$$

Combine like terms in y+2zy-6z-2yz.

$$\frac{y-6z}{4xyz}$$