Solve 1/xx

$$\frac{ 1 }{ xx }$$

Differentiate w.r.t. x

$$-\frac{2}{x^{3}}$$

Steps Using Chain Rule

Multiply x and x to get x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{x^{2}})$$

If F is the composition of two differentiable functions f\left(u\right) and u=g\left(x\right), that is, if F\left(x\right)=f\left(g\left(x\right)\right), then the derivative of F is the derivative of f with respect to u times the derivative of g with respect to x, that is, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(x^{2}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-\left(x^{2}\right)^{-2}\times 2x^{2-1}$$

Simplify.

$$-2x^{1}\left(x^{2}\right)^{-2}$$

For any term t, t^{1}=t.

$$-2x\left(x^{2}\right)^{-2}$$

Evaluate

$$\frac{1}{x^{2}}$$

Solution Steps

Multiply x and x to get x^{2}.

$$\frac{1}{x^{2}}$$