Solve for x
x\neq 2
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1+x-2=-\left(1-x\right)
Variable x cannot be equal to 2 since division by zero is not defined. Multiply both sides of the equation by x-2, the least common multiple of x-2,2-x.
-1+x=-\left(1-x\right)
Subtract 2 from 1 to get -1.
-1+x=-1+x
To find the opposite of 1-x, find the opposite of each term.
-1+x-x=-1
Subtract x from both sides.
-1=-1
Combine x and -x to get 0.
\text{true}
Compare -1 and -1.
x\in \mathrm{R}
This is true for any x.
x\in \mathrm{R}\setminus 2
Variable x cannot be equal to 2.
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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