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\frac{1}{5}x+2+\frac{1}{4}x=\frac{3}{4}
Add \frac{1}{4}x to both sides.
\frac{9}{20}x+2=\frac{3}{4}
Combine \frac{1}{5}x and \frac{1}{4}x to get \frac{9}{20}x.
\frac{9}{20}x=\frac{3}{4}-2
Subtract 2 from both sides.
\frac{9}{20}x=\frac{3}{4}-\frac{8}{4}
Convert 2 to fraction \frac{8}{4}.
\frac{9}{20}x=\frac{3-8}{4}
Since \frac{3}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{9}{20}x=-\frac{5}{4}
Subtract 8 from 3 to get -5.
x=-\frac{5}{4}\times \frac{20}{9}
Multiply both sides by \frac{20}{9}, the reciprocal of \frac{9}{20}.
x=\frac{-5\times 20}{4\times 9}
Multiply -\frac{5}{4} times \frac{20}{9} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-100}{36}
Do the multiplications in the fraction \frac{-5\times 20}{4\times 9}.
x=-\frac{25}{9}
Reduce the fraction \frac{-100}{36} to lowest terms by extracting and canceling out 4.