Solve 1/49*2+1/10

$$\frac{ 1 }{ 49 \times 2 } + \frac{ 1 }{ 10 }$$

Evaluate

$$\frac{27}{245}\approx 0.110204082$$

Solution Steps

Multiply 49 and 2 to get 98.

$$\frac{1}{98}+\frac{1}{10}$$

Least common multiple of 98 and 10 is 490. Convert \frac{1}{98} and \frac{1}{10} to fractions with denominator 490.

$$\frac{5}{490}+\frac{49}{490}$$

Since \frac{5}{490} and \frac{49}{490} have the same denominator, add them by adding their numerators.

$$\frac{5+49}{490}$$

Add 5 and 49 to get 54.

$$\frac{54}{490}$$

Reduce the fraction \frac{54}{490} to lowest terms by extracting and canceling out 2.

$$\frac{27}{245}$$

Factor

$$\frac{3 ^ {3}}{5 \cdot 7 ^ {2}} = 0.11020408163265306$$