Solve 1/4p=3/4-16+9

$$\frac{ 1 }{ 4 } p = \frac{ 3 }{ 4 } -16+9$$

Solve for p

$$p=-25$$

Steps for Solving Linear Equation

Convert 16 to fraction \frac{64}{4}.

$$\frac{1}{4}p=\frac{3}{4}-\frac{64}{4}+9$$

Since \frac{3}{4} and \frac{64}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{4}p=\frac{3-64}{4}+9$$

Subtract 64 from 3 to get -61.

$$\frac{1}{4}p=-\frac{61}{4}+9$$

Convert 9 to fraction \frac{36}{4}.

$$\frac{1}{4}p=-\frac{61}{4}+\frac{36}{4}$$

Since -\frac{61}{4} and \frac{36}{4} have the same denominator, add them by adding their numerators.

$$\frac{1}{4}p=\frac{-61+36}{4}$$

Add -61 and 36 to get -25.

$$\frac{1}{4}p=-\frac{25}{4}$$

Multiply both sides by 4, the reciprocal of \frac{1}{4}.

$$p=-\frac{25}{4}\times 4$$

Cancel out 4 and 4.

$$p=-25$$