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\frac{3-2\sqrt{2}}{\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)}
Rationalize the denominator of \frac{1}{3+2\sqrt{2}} by multiplying numerator and denominator by 3-2\sqrt{2}.
\frac{3-2\sqrt{2}}{3^{2}-\left(2\sqrt{2}\right)^{2}}
Consider \left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{3-2\sqrt{2}}{9-\left(2\sqrt{2}\right)^{2}}
Calculate 3 to the power of 2 and get 9.
\frac{3-2\sqrt{2}}{9-2^{2}\left(\sqrt{2}\right)^{2}}
Expand \left(2\sqrt{2}\right)^{2}.
\frac{3-2\sqrt{2}}{9-4\left(\sqrt{2}\right)^{2}}
Calculate 2 to the power of 2 and get 4.
\frac{3-2\sqrt{2}}{9-4\times 2}
The square of \sqrt{2} is 2.
\frac{3-2\sqrt{2}}{9-8}
Multiply 4 and 2 to get 8.
\frac{3-2\sqrt{2}}{1}
Subtract 8 from 9 to get 1.
3-2\sqrt{2}
Anything divided by one gives itself.