Solve 1/3x+12=x

$$\frac{ 1 }{ 3 } x+12=x$$

Solve for x

$$x=18$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$\frac{1}{3}x+12-x=0$$

Combine \frac{1}{3}x and -x to get -\frac{2}{3}x.

$$-\frac{2}{3}x+12=0$$

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$-\frac{2}{3}x=-12$$

Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.

$$x=-12\left(-\frac{3}{2}\right)$$

Express -12\left(-\frac{3}{2}\right) as a single fraction.

$$x=\frac{-12\left(-3\right)}{2}$$

Multiply -12 and -3 to get 36.

$$x=\frac{36}{2}$$

Divide 36 by 2 to get 18.

$$x=18$$