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\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x+\frac{2}{5}\left(-\frac{3}{4}\right)
Use the distributive property to multiply \frac{2}{5} by x-\frac{3}{4}.
\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x+\frac{2\left(-3\right)}{5\times 4}
Multiply \frac{2}{5} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.
\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x+\frac{-6}{20}
Do the multiplications in the fraction \frac{2\left(-3\right)}{5\times 4}.
\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x-\frac{3}{10}
Reduce the fraction \frac{-6}{20} to lowest terms by extracting and canceling out 2.
\frac{1}{3}x+\frac{1}{4}-\frac{2}{5}x=-\frac{3}{10}
Subtract \frac{2}{5}x from both sides.
-\frac{1}{15}x+\frac{1}{4}=-\frac{3}{10}
Combine \frac{1}{3}x and -\frac{2}{5}x to get -\frac{1}{15}x.
-\frac{1}{15}x=-\frac{3}{10}-\frac{1}{4}
Subtract \frac{1}{4} from both sides.
-\frac{1}{15}x=-\frac{6}{20}-\frac{5}{20}
Least common multiple of 10 and 4 is 20. Convert -\frac{3}{10} and \frac{1}{4} to fractions with denominator 20.
-\frac{1}{15}x=\frac{-6-5}{20}
Since -\frac{6}{20} and \frac{5}{20} have the same denominator, subtract them by subtracting their numerators.
-\frac{1}{15}x=-\frac{11}{20}
Subtract 5 from -6 to get -11.
x=-\frac{11}{20}\left(-15\right)
Multiply both sides by -15, the reciprocal of -\frac{1}{15}.
x=\frac{-11\left(-15\right)}{20}
Express -\frac{11}{20}\left(-15\right) as a single fraction.
x=\frac{165}{20}
Multiply -11 and -15 to get 165.
x=\frac{33}{4}
Reduce the fraction \frac{165}{20} to lowest terms by extracting and canceling out 5.