Solve 1/3+4/1-4/32/6=frac{1}{4}

$$\frac{ 1 }{ 3 } + \frac{ 4 }{ 1 } - \frac{ 4 }{ 3 } \frac{ 2 }{ 6 } = \frac{ 1 }{ 4 }$$

Verify

Solution Steps

Anything divided by one gives itself.

$$\frac{1}{3}+4-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{1}{3}+\frac{12}{3}-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Since \frac{1}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{1+12}{3}-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Add 1 and 12 to get 13.

$$\frac{13}{3}-\frac{4}{3}\times \frac{2}{6}=\frac{1}{4}$$

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{13}{3}-\frac{4}{3}\times \frac{1}{3}=\frac{1}{4}$$

Multiply \frac{4}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{13}{3}-\frac{4\times 1}{3\times 3}=\frac{1}{4}$$

Do the multiplications in the fraction \frac{4\times 1}{3\times 3}.

$$\frac{13}{3}-\frac{4}{9}=\frac{1}{4}$$

Least common multiple of 3 and 9 is 9. Convert \frac{13}{3} and \frac{4}{9} to fractions with denominator 9.

$$\frac{39}{9}-\frac{4}{9}=\frac{1}{4}$$

Since \frac{39}{9} and \frac{4}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{39-4}{9}=\frac{1}{4}$$

Subtract 4 from 39 to get 35.

$$\frac{35}{9}=\frac{1}{4}$$

Least common multiple of 9 and 4 is 36. Convert \frac{35}{9} and \frac{1}{4} to fractions with denominator 36.

$$\frac{140}{36}=\frac{9}{36}$$

Compare \frac{140}{36} and \frac{9}{36}.

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