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Solve for x_2
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3x_{2}\times \frac{1}{3}+3=-5x_{2}
Variable x_{2} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x_{2}, the least common multiple of 3,x_{2}.
x_{2}+3=-5x_{2}
Cancel out 3 and 3.
x_{2}+3+5x_{2}=0
Add 5x_{2} to both sides.
6x_{2}+3=0
Combine x_{2} and 5x_{2} to get 6x_{2}.
6x_{2}=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
x_{2}=\frac{-3}{6}
Divide both sides by 6.
x_{2}=-\frac{1}{2}
Reduce the fraction \frac{-3}{6} to lowest terms by extracting and canceling out 3.