Solve 1/2(-2^3)3^2+3(-2^2)4^2

$$\frac{ 1 }{ 2 } (- { 2 }^{ 3 } ) { 3 }^{ 2 } +3(- { 2 }^{ 2 } ) { 4 }^{ 2 }$$

Evaluate

$$-228$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{2}\left(-8\right)\times 3^{2}+3\left(-2^{2}\right)\times 4^{2}$$

Multiply \frac{1}{2} and -8 to get \frac{-8}{2}.

$$\frac{-8}{2}\times 3^{2}+3\left(-2^{2}\right)\times 4^{2}$$

Divide -8 by 2 to get -4.

$$-4\times 3^{2}+3\left(-2^{2}\right)\times 4^{2}$$

Calculate 3 to the power of 2 and get 9.

$$-4\times 9+3\left(-2^{2}\right)\times 4^{2}$$

Multiply -4 and 9 to get -36.

$$-36+3\left(-2^{2}\right)\times 4^{2}$$

Calculate 2 to the power of 2 and get 4.

$$-36+3\left(-4\right)\times 4^{2}$$

Multiply 3 and -4 to get -12.

$$-36-12\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-36-12\times 16$$

Multiply -12 and 16 to get -192.

$$-36-192$$

Subtract 192 from -36 to get -228.

$$-228$$

Factor

$$-228$$