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\frac{1}{2}x^{2}-x=0
Subtract x from both sides.
x\left(\frac{1}{2}x-1\right)=0
Factor out x.
x=0 x=2
To find equation solutions, solve x=0 and \frac{x}{2}-1=0.
\frac{1}{2}x^{2}-x=0
Subtract x from both sides.
x=\frac{-\left(-1\right)±\sqrt{1}}{2\times \frac{1}{2}}
This equation is in standard form: ax^{2}+bx+c=0. Substitute \frac{1}{2} for a, -1 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-1\right)±1}{2\times \frac{1}{2}}
Take the square root of 1.
x=\frac{1±1}{2\times \frac{1}{2}}
The opposite of -1 is 1.
x=\frac{1±1}{1}
Multiply 2 times \frac{1}{2}.
x=\frac{2}{1}
Now solve the equation x=\frac{1±1}{1} when ± is plus. Add 1 to 1.
x=2
Divide 2 by 1.
x=\frac{0}{1}
Now solve the equation x=\frac{1±1}{1} when ± is minus. Subtract 1 from 1.
x=0
Divide 0 by 1.
x=2 x=0
The equation is now solved.
\frac{1}{2}x^{2}-x=0
Subtract x from both sides.
\frac{\frac{1}{2}x^{2}-x}{\frac{1}{2}}=\frac{0}{\frac{1}{2}}
Multiply both sides by 2.
x^{2}+\left(-\frac{1}{\frac{1}{2}}\right)x=\frac{0}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
x^{2}-2x=\frac{0}{\frac{1}{2}}
Divide -1 by \frac{1}{2} by multiplying -1 by the reciprocal of \frac{1}{2}.
x^{2}-2x=0
Divide 0 by \frac{1}{2} by multiplying 0 by the reciprocal of \frac{1}{2}.
x^{2}-2x+1=1
Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
\left(x-1\right)^{2}=1
Factor x^{2}-2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
x-1=1 x-1=-1
Simplify.
x=2 x=0
Add 1 to both sides of the equation.