Solve 1/{left(frac{7{8}right)}^2+10}

$$\frac{ 1 }{ { \left( \frac{ 7 }{ 8 } \right) }^{ 2 } +10 }$$

Evaluate

$$\frac{64}{689}\approx 0.092888244$$

Solution Steps

Calculate \frac{7}{8} to the power of 2 and get \frac{49}{64}.

$$\frac{1}{\frac{49}{64}+10}$$

Convert 10 to fraction \frac{640}{64}.

$$\frac{1}{\frac{49}{64}+\frac{640}{64}}$$

Since \frac{49}{64} and \frac{640}{64} have the same denominator, add them by adding their numerators.

$$\frac{1}{\frac{49+640}{64}}$$

Add 49 and 640 to get 689.

$$\frac{1}{\frac{689}{64}}$$

Divide 1 by \frac{689}{64} by multiplying 1 by the reciprocal of \frac{689}{64}.

$$1\times \frac{64}{689}$$

Multiply 1 and \frac{64}{689} to get \frac{64}{689}.

$$\frac{64}{689}$$

Factor

$$\frac{2 ^ {6}}{13 \cdot 53} = 0.09288824383164006$$