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\frac{\sqrt{3}-2}{\left(\sqrt{3}+2\right)\left(\sqrt{3}-2\right)}
Rationalize the denominator of \frac{1}{\sqrt{3}+2} by multiplying numerator and denominator by \sqrt{3}-2.
\frac{\sqrt{3}-2}{\left(\sqrt{3}\right)^{2}-2^{2}}
Consider \left(\sqrt{3}+2\right)\left(\sqrt{3}-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\sqrt{3}-2}{3-4}
Square \sqrt{3}. Square 2.
\frac{\sqrt{3}-2}{-1}
Subtract 4 from 3 to get -1.
-\sqrt{3}-\left(-2\right)
Anything divided by -1 gives its opposite. To find the opposite of \sqrt{3}-2, find the opposite of each term.
-\sqrt{3}+2
The opposite of -2 is 2.