Solve 01^2/left(10^-6right)^2=0*1/x

$$\frac{ 0 { 1 }^{ 2 } }{ { \left( { 10 }^{ -6 } \right) }^{ 2 } } = \frac{ 0 \cdot 1 }{ x }$$

Solve for x

$$x\neq 0$$

Solution Steps

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$1000000000000x\times 0\times 1^{2}=0\times 1$$

Multiply 1000000000000 and 0 to get 0.

$$0x\times 1^{2}=0\times 1$$

Calculate 1 to the power of 2 and get 1.

$$0x\times 1=0\times 1$$

Multiply 0 and 1 to get 0.

$$0x=0\times 1$$

Anything times zero gives zero.

$$0=0\times 1$$

Multiply 0 and 1 to get 0.

$$0=0$$

Compare 0 and 0.

$$\text{true}$$

This is true for any x.

$$x\in \mathrm{R}$$

Variable x cannot be equal to 0.

$$x\in \mathrm{R}\setminus 0$$