Solve -9*2(3-6)/left|4^2-2^5right|-6

$$\frac{ -9 \times 2(3-6) }{ \left| { 4 }^{ 2 } - { 2 }^{ 5 } \right| -6 }$$

Evaluate

$$\frac{27}{5}=5.4$$

Solution Steps

Multiply -9 and 2 to get -18.

$$\frac{-18\left(3-6\right)}{|4^{2}-2^{5}|-6}$$

Subtract 6 from 3 to get -3.

$$\frac{-18\left(-3\right)}{|4^{2}-2^{5}|-6}$$

Multiply -18 and -3 to get 54.

$$\frac{54}{|4^{2}-2^{5}|-6}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{54}{|16-2^{5}|-6}$$

Calculate 2 to the power of 5 and get 32.

$$\frac{54}{|16-32|-6}$$

Subtract 32 from 16 to get -16.

$$\frac{54}{|-16|-6}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -16 is 16.

$$\frac{54}{16-6}$$

Subtract 6 from 16 to get 10.

$$\frac{54}{10}$$

Reduce the fraction \frac{54}{10} to lowest terms by extracting and canceling out 2.

$$\frac{27}{5}$$

Factor

$$\frac{3 ^ {3}}{5} = 5\frac{2}{5} = 5.4$$