Solve -7xy/7xy

$$\frac{ -7xy }{ 7xy }$$

Evaluate

$$-1$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{\left(-7\right)^{1}x^{1}y^{1}}{7^{1}x^{1}y^{1}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\left(-7\right)^{1}}{7^{1}}x^{1-1}y^{1-1}$$

Subtract 1 from 1.

$$\frac{\left(-7\right)^{1}}{7^{1}}x^{0}y^{1-1}$$

For any number a except 0, a^{0}=1.

$$\frac{\left(-7\right)^{1}}{7^{1}}y^{1-1}$$

Subtract 1 from 1.

$$\frac{\left(-7\right)^{1}}{7^{1}}y^{0}$$

For any number a except 0, a^{0}=1.

$$\frac{\left(-7\right)^{1}}{7^{1}}$$

Divide -7 by 7.

$$-1$$

Factor

$$-1$$