Solve -2x^2/25+x-5

$$\frac{ -2 { x }^{ 2 } }{ 25 } +x-5$$

Evaluate

$$-\frac{2x^{2}}{25}+x-5$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x-5 times \frac{25}{25}.

$$\frac{-2x^{2}}{25}+\frac{25\left(x-5\right)}{25}$$

Since \frac{-2x^{2}}{25} and \frac{25\left(x-5\right)}{25} have the same denominator, add them by adding their numerators.

$$\frac{-2x^{2}+25\left(x-5\right)}{25}$$

Do the multiplications in -2x^{2}+25\left(x-5\right).

$$\frac{-2x^{2}+25x-125}{25}$$

Factor

$$\frac{-2x^{2}+25x-125}{25}$$

Solution Steps

Factor out \frac{1}{25}. Polynomial -2x^{2}+25x-125 is not factored since it does not have any rational roots.

$$\frac{-2x^{2}+25x-125}{25}$$