Solve -17left(3+hright)left(3-6right)+h-153/h

$$\frac{ -17 \left( 3+h \right) \left( 3-6 \right) +h-153 }{ h }$$

Evaluate

$$52$$

Short Solution Steps

Subtract 6 from 3 to get -3.

$$\frac{-17\left(3+h\right)\left(-3\right)+h-153}{h}$$

Multiply -17 and -3 to get 51.

$$\frac{51\left(3+h\right)+h-153}{h}$$

Factor the expressions that are not already factored.

$$\frac{52h}{h}$$

Cancel out h in both numerator and denominator.

$$52$$

Factor

$$2^{2}\times 13$$