Solve (32*3)+(27+3)+(33+4+37)+23+23/10

$$\frac{ (32 \cdot 3)+(27+3)+(33+4+37)+23+23 }{ 10 }$$

Evaluate

$$\frac{123}{5}=24.6$$

Solution Steps

Multiply 32 and 3 to get 96.

$$\frac{96+27+3+33+4+37+23+23}{10}$$

Add 96 and 27 to get 123.

$$\frac{123+3+33+4+37+23+23}{10}$$

Add 123 and 3 to get 126.

$$\frac{126+33+4+37+23+23}{10}$$

Add 126 and 33 to get 159.

$$\frac{159+4+37+23+23}{10}$$

Add 159 and 4 to get 163.

$$\frac{163+37+23+23}{10}$$

Add 163 and 37 to get 200.

$$\frac{200+23+23}{10}$$

Add 200 and 23 to get 223.

$$\frac{223+23}{10}$$

Add 223 and 23 to get 246.

$$\frac{246}{10}$$

Reduce the fraction \frac{246}{10} to lowest terms by extracting and canceling out 2.

$$\frac{123}{5}$$

Factor

$$\frac{3 \cdot 41}{5} = 24\frac{3}{5} = 24.6$$