Solve (3.2*3)+(2.7+3)+(3.3+4+3.7)+2.3+2.3/10

$$\frac{ (3.2 \cdot 3)+(2.7+3)+(3.3+4+3.7)+2.3+2.3 }{ 10 }$$

Evaluate

$$3.09$$

Solution Steps

Multiply 3.2 and 3 to get 9.6.

$$\frac{9.6+2.7+3+3.3+4+3.7+2.3+2.3}{10}$$

Add 9.6 and 2.7 to get 12.3.

$$\frac{12.3+3+3.3+4+3.7+2.3+2.3}{10}$$

Add 12.3 and 3 to get 15.3.

$$\frac{15.3+3.3+4+3.7+2.3+2.3}{10}$$

Add 15.3 and 3.3 to get 18.6.

$$\frac{18.6+4+3.7+2.3+2.3}{10}$$

Add 18.6 and 4 to get 22.6.

$$\frac{22.6+3.7+2.3+2.3}{10}$$

Add 22.6 and 3.7 to get 26.3.

$$\frac{26.3+2.3+2.3}{10}$$

Add 26.3 and 2.3 to get 28.6.

$$\frac{28.6+2.3}{10}$$

Add 28.6 and 2.3 to get 30.9.

$$\frac{30.9}{10}$$

Expand \frac{30.9}{10} by multiplying both numerator and the denominator by 10.

$$\frac{309}{100}$$

Factor

$$\frac{3 \cdot 103}{2 ^ {2} \cdot 5 ^ {2}} = 3\frac{9}{100} = 3.09$$